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Comparing Exponential Values: When Is 8^9 Greater Than 9^8?
Comparing Exponential Values: When Is 89 Greater Than 98?
Many times, we encounter situations where we need to compare exponential values. In this article, we will explore how to determine if 89 is greater than 98. We will present both direct calculation and logarithmic methods to solve this problem accurately and efficiently.
Direct Calculation
To directly calculate the values, we start by expressing 89 and 98 in terms of simpler exponential forms:
For 89:
89 23^9 227 134,217,728
For 98:
98 32^8 316 430,467,216
By comparing the values, it is clear that:
89 134,217,728 8. Therefore, 89 is not greater than 98.
Using Logarithms for Comparison
To compare 89 and 98 using logarithms, we take the logarithm of both expressions:
log 89 9 log 8
log 98 8 log 9
We need to compare 9 log 8 and 8 log 9. To do this, we rearrange the expression as follows:
9 log 8 / 8 log 9 or log 8 / log 9
We need approximate values for log 8 and log 9:
log 8 3 log 2 ≈ 3 × 0.301 0.903
log 9 2 log 3 ≈ 2 × 0.477 0.954
Calculating:
9 log 8 / 8 log 9 ≈ (9 × 0.903) / (8 × 0.954) ≈ 8.127 / 7.632 ≈ 1.064
This indicates that 8 log 9 > 9 log 8, which means:
89 > 98
Another Example: 898 vs. 989
Let's now explore another example: which is larger between 898 and 989. First, we simplify the expressions:
For 898:
898 238 227
For 989:
989 329 316
Comparing these values by comparing the logarithms of these numbers, since the function log x is increasing:
log 898 8 log 89 8 log 23 27 log 2
log 989 9 log 98 9 log 32 16 log 3
We need to compare 27 log 2 and 16 log 3. Calculating approximate values:
log 2 ≈ 0.3010
log 3 ≈ 0.4771
Calculating:
27 log 2 ≈ 27 × 0.3010 8.127
16 log 3 ≈ 16 × 0.4771 7.617
Since 27 log 2 > 16 log 3, we have:
898 > 989
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