How to Compute the Sum of Even Numbers from 1 to 20: A Comprehensive Guide

Whether you're a beginner in programming or just looking for quick solutions, here's a step-by-step guide on how to write a basic program that computes the sum of even numbers from 1 to 20 in various programming languages. This guide will include detailed explanations and source code snippets for C, Python, JavaScript, Java, and Let's dive in!

Overview of the Problem

The task at hand is to write a program that sums all even numbers between 1 and 20. An even number is any integer that is divisible by 2. We will cover the solution in several popular programming languages, ensuring that you can find the appropriate code for your preferred environment.

Solution in C

Here is a basic program written in the C language:

#includestdio.h int main() { int sum 0, i; for (i 1; i lt 20; i ) { if (i % 2 0) { sum i; } } printf(Sum of even numbers between 1 and 20 is: %d, sum); return 0; }

Explanation:

Looping: The program uses a for loop to iterate through numbers from 1 to 20. Even Check: The condition if (i % 2 0) checks if the number is even by using the modulo operator. Summation: Even numbers are added to the sum variable.

Solution in Python

Here is the equivalent program in Python:

sum_even 0 for num in range(1, 21): if num % 2 0: sum_even num print(The sum of even numbers from 1 to 20 is: , sum_even)

Explanation:

Looping: The program uses a for loop with range(1, 21) to iterate through numbers from 1 to 20. Even Check: The condition if num % 2 0 checks if the number is even. Summation: Even numbers are added to the sum_even variable.

Solution in JavaScript

Here is the equivalent program in JavaScript:

let sumEven 0; for (let num 1; num lt 20; num ) { if (num % 2 0) { sumEven num; } } console.log(The sum of even numbers from 1 to 20 is: , sumEven);

Explanation:

Looping: The program uses a for loop to iterate through numbers from 1 to 20. Even Check: The condition if (num % 2 0) checks if the number is even. Summation: Even numbers are added to the sumEven variable.

Solution in Java

Here is the equivalent program in Java:

public class SumEvenNumbers { public static void main(String[] args) { int sumEven 0; for (int num 1; num lt 20; num ) { if (num % 2 0) { sumEven num; } } (The sum of even numbers from 1 to 20 is: sumEven); } }

Explanation:

Looping: The program uses a for loop to iterate through numbers from 1 to 20. Even Check: The condition if (num % 2 0) checks if the number is even. Summation: Even numbers are added to the sumEven variable.

Solution in

Here is the equivalent program in

Module EvenNumberSum Sub Main() Dim sum As Integer 0 For i As Integer 1 To 20 If i Mod 2 0 Then sum i End If Next Console.WriteLine(The sum of even numbers from 1 to 20 is: sum) End Sub End Module

Explanation:

Looping: The program uses a For loop to iterate through numbers from 1 to 20. Even Check: The condition If i Mod 2 0 Then checks if the number is even. Summation: Even numbers are added to the sum variable.

Conclusion

The expected output for all the above programs is as follows:

The sum of even numbers from 1 to 20 is: 110

Each of these solutions uses the same basic logic of looping through numbers, checking if they are even, and then summing the even numbers.

By understanding and implementing these programs, you can easily compute the sum of even numbers in various programming languages. This guide should help you tackle similar problems in the future. Happy coding!