TechTorch

Location:HOME > Technology > content

Technology

How to Solve and Integrate the Exponential Fourier Series

April 07, 2025Technology4614
How to Solve and Integrate the Exponential Fourier Series Understandin

How to Solve and Integrate the Exponential Fourier Series

Understanding and solving the integral of exponential Fourier series can be complex, especially when dealing with functions of the form ( frac{e^{-x/a}}{1 - ax} ). This article provides a step-by-step guide to integrating such expressions, using advanced mathematical techniques and functions, including the Exponential Integral.

Step-by-Step Solution

The given integral is ( int_0^b frac{e^{-x/a}}{1 - ax} , dx ). The solution involves several transformations and the introduction of the Exponential Integral function. Here's how the process works:

Step 1: Variable Substitution

First, let ( t 1 - ax ). This transforms the integral and introduces a new variable ( t ) that simplifies the expression. The differential ( dt ) is found to be ( dt -a , dx ), which changes the limits of integration and the integrand. With these transformations, the integral becomes:

[ int_0^b frac{e^{-x/a}}{1 - ax} , dx int_1^{1-ab} frac{e^{-t-1/a^2}}{t} , frac{dt}{a} frac{e^{1/a^2}}{a} int_1^{1-ab} frac{e^{-t/a^2}}{t} , dt. ]

Step 2: Further Substitution

To simplify the integrand further, use the substitution ( w frac{t}{a^2} ). The differential ( dw ) is calculated as ( dw frac{1}{a^2} , dt ), which leads to the integral being rewritten in terms of ( w ):

[ frac{e^{1/a^2}}{a} int_{frac{1}{a^2}}^{frac{1-ab}{a^2}} frac{e^{-w}}{w} , dw. ]

Step 3: Utilize the Exponential Integral Function

The integral ( int frac{e^{-w}}{w} , dw ) is known as the Exponential Integral function, denoted as ( text{Ei}(x) ). Therefore, the integral can be expressed as:

[ frac{e^{1/a^2}}{a} Big[int_{frac{1}{a^2}}^{infty} frac{e^{-w}}{w} , dw - int_{frac{1-ab}{a^2}}^{infty} frac{e^{-w}}{w} , dw Big]. ]

Final Result

By applying the definition of the Exponential Integral function, the solution to the original integral can be written as:

[ int_0^b frac{e^{-x/a}}{1 - ax} , dx frac{e^{1/a^2}}{a} Big[ text{Ei}Big( -frac{1-ab}{a^2} Big) - text{Ei}Big( -frac{1}{a^2} Big) Big]. ]

Conclusion

The solution provided demonstrates the use of substitution techniques and the Exponential Integral function to solve a complex integral. Understanding these advanced mathematical tools is essential for tackling problems in various fields, including physics and engineering, where similar forms of integrals often appear.