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Proving the Law of Sines Using the Law of Cosines

June 26, 2025Technology1939
Proving the Law of Sines Using the Law of Cosines In this article, we

Proving the Law of Sines Using the Law of Cosines

In this article, we will explore the relationship between the Law of Cosines and the Law of Sines. We will provide a step-by-step proof to establish the Law of Sines using the Law of Cosines and the concept of triangle area.

Introduction

The Law of Sines and the Law of Cosines are fundamental principles in trigonometry and are widely used to solve problems involving triangles. While the Law of Cosines involves the sides and angles of a triangle, the Law of Sines relates the ratio of the lengths of the sides of a triangle to the sines of its angles. In this article, we will show how to derive the Law of Sines using the Law of Cosines and the concept of the area of a triangle.

Proof of the Law of Sines Using the Law of Cosines

Consider a triangle (ABC) with sides (a), (b), and (c) opposite to angles (A), (B), and (C) respectively. We will start with the Law of Cosines and use it to derive the Law of Sines.

Step 1: Using the Law of Cosines

The Law of Cosines states:

(c^2 a^2 b^2 - 2ab cos C) (a^2 b^2 c^2 - 2bc cos A) (b^2 a^2 c^2 - 2ac cos B)

These equations allow us to express the cosine of an angle in terms of the sides of the triangle.

Step 2: Rearranging the Law of Cosines

From the first equation, we can express (cos C):

(cos C frac{a^2 b^2 - c^2}{2ab})

Step 3: Area of Triangle Using Sine

The area (K) of triangle (ABC) can be expressed using the sine of one of its angles:

(K frac{1}{2}ab sin C)

We can also express the area using the side (c) and angle (C):

(K frac{1}{2}bc sin A)

(K frac{1}{2}ac sin B)

Step 4: Equating the Area Expressions

Now, we have three expressions for the area (K):

(K frac{1}{2}ab sin C) (K frac{1}{2}bc sin A) (K frac{1}{2}ac sin B)

Setting these equal to each other, we get:

(frac{ab sin C}{2} frac{bc sin A}{2})

From this, we get:

(frac{sin A}{a} frac{sin C}{c}) (1)

Similarly, using the second and third area expressions, we can derive:

(frac{bc sin A}{2} frac{ac sin B}{2})

From this, we get:

(frac{sin B}{b} frac{sin A}{a}) (2)

Step 5: Conclusion

From equations (1) and (2), we can see that:

(frac{sin A}{a} frac{sin B}{b} frac{sin C}{c})

This is the Law of Sines, which can be written as:

(frac{a}{sin A} frac{b}{sin B} frac{c}{sin C})

We have therefore proved the Law of Sines using the Law of Cosines and the concept of the area of a triangle.

Conclusion

The proof of the Law of Sines through the Law of Cosines provides a deeper understanding of the relationships between the sides and angles of a triangle. This proof is particularly useful for those studying trigonometry and geometry, as it demonstrates the interconnectedness of different trigonometric principles.

Keywords: Law of Cosines, Law of Sines, Triangle Area, Mathematical Proof