TechTorch

Location:HOME > Technology > content

Technology

Riemann vs Lebesgue Integrability: The Function sin(x)/x on [0, 1]

April 20, 2025Technology3084
Understanding the Function sin(x)/x on the Interval [0, 1] This articl

Understanding the Function sin(x)/x on the Interval [0, 1]

This article delves into the behavior of the function sin(x)/x on the interval [0, 1] as it pertains to two different types of integration: Riemann and Lebesgue. We will examine why this function is Riemann integrable but not Lebesgue integrable. This distinction is crucial in the field of mathematical analysis and has profound implications for various applications in mathematics, physics, and engineering.

Riemann Integrability of sin(x)/x

The function sin(x)/x is a classic example of a function that is Riemann integrable over the interval [0, 1]. This is due to the properties of the function within this interval:

Continuity: The function sin(x)/x is continuous everywhere except at x 0, where it has a removable discontinuity. Specifically, the limit of sin(x)/x as x approaches 0 is 1, making the function continuous at this point after adjusting the value at x 0. Boundedness: The function sin(x)/x is bounded on the interval [0, 1]. This can be seen from the fact that sin(x)/x ≤ 1 for all x in [0, 1], and since sin(x) is always between -1 and 1, the quotient remains within a finite range.

Given these properties, the function sin(x)/x satisfies the conditions required for Riemann integrability on the interval [0, 1].

Lebesgue Integrability and the Failure to Satisfy Conditions

In contrast, the function sin(x)/x is not Lebesgue integrable on the interval [0, 1]. This is a more nuanced property that requires a deeper understanding of measure theory and integration:

Lebesgue Integrability: A function is Lebesgue integrable if its absolute value is Lebesgue integrable. In the case of sin(x)/x, the absolute value of the function, |sin(x)/x|, is not Lebesgue integrable on the interval [0, 1]. Divergence of the Integral: The integral of |sin(x)/x| from 0 to 1 is divergent. This can be shown using the fact that the integral of 1/x diverges over the same interval, and the comparison test demonstrates that |sin(x)/x| is essentially comparable to 1/x in terms of its divergence properties.

The failure of |sin(x)/x| to be integrable leads to the conclusion that the function itself is not Lebesgue integrable.

Additional Insights and Calculations

Despite the function's non-Lebesgue integrability, there are interesting ways to calculate the improper Riemann integral of sin(x)/x. One such method involves complex analysis, where the integral can be evaluated by considering the complex exponential function:

Using Euler's formula, sin(z) Im(e^(iz)). By applying this identity and using techniques from complex analysis, it is possible to compute the integral in a surprising and elegant manner.

This approach reveals the beauty of mathematical analysis and opens up further avenues for exploration in advanced mathematics.

Conclusion

The function sin(x)/x serves as a critical example in the study of different types of integrals. Its Riemann integrability on [0, 1], which is due to its continuity and boundedness, stands in stark contrast to its non-Lebesgue integrability, a result of the properties of its absolute value function. This interplay between Riemann and Lebesgue integrals is fundamental for deepening one's understanding of measure theory and functional analysis.

References

Wikipedia Riemann Integral Wikipedia Lebesgue Integration Math Stack Exchange Proof