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Writing an 8086 Assembly Language Program to Check for Strong Numbers
Writing an 8086 Assembly Language Program to Check for Strong Numbers
Understanding Strong Numbers
A strong number is a number where the sum of the factorials of its digits equals the number itself. For example, 145 is a strong number because 1! 4! 5! 1 24 120 145. This article will guide you through writing an 8086 assembly language program to check if a given number is a strong number, using the console as the input source.
Steps to Write the Program
Input the number: Read a number from the console. Extract digits: Extract each digit of the number. Calculate factorials: Calculate the factorial of each digit. Sum the factorials: Sum all the factorials of the digits. Compare the sum: Check if the sum equals the original number.Sample 8086 Assembly Program
Below is a simple implementation of the above logic in 8086 assembly language:
#35; Model small .stack 100h .data num db 5 dup(0) ; Buffer to store the input number msg db 'Enter a number:#39;, 0Dh, 0Ah result_msg db 'The number is a strong number.', 0Dh, 0Ah not_strong_msg db 'The number is not a strong number.', 0Dh, 0Ah newline db 13, 10 .code main proc mov ax, @data mov ds, ax ; Prompt for input lea dx, msg mov ah, 09h int 21h ; Read the number lea dx, num mov ah, 0Ah int 21h ; Convert input string to number mov si, offset num 1 ; Point to the first digit xor cx, cx ; Clear digit counter mov cl, [num] ; Number of digits xor ax, ax ; Clear AX for the number .convert_loop: movzx bx, byte ptr [si] ; Get digit sub bx, '0' ; Convert from ASCII to integer mov dx, 10 ; Multiply by 10 mul dx ; AX AX * 10 add ax, bx ; AX digit inc si ; Move to next digit loop .convert_loop ; Store original number mov bx, ax ; BX original number xor cx, cx ; Clear CX for factorial sum ; Calculate sum of factorials lea si, num 1 ; Point to first digit .factorial_loop: movzx bx, byte ptr [si] ; Get digit sub bx, '0' ; Convert from ASCII to integer call factorial ; Calculate factorial add cx, ax ; Sum the factorials inc si ; Move to next digit cmp si, num 1 ; Check if we reached the end jl .factorial_loop ; Compare the sum of factorials with the original number cmp cx, bx ; Compare sum with original number je .is_strong ; If equal, it's a strong number ; Output not strong message lea dx, not_strong_msg mov ah, 09h int 21h jmp .done .is_strong: ; Output strong message lea dx, result_msg mov ah, 09h int 21h .done: ; New line lea dx, newline mov ah, 09h int 21h ; Exit program mov ax, 4C00h int 21h factorial proc ; Input: BX digit (0-9) ; Output: AX factorial of BX mov ax, 1 ; AX factorial result cmp bx, 0 je .factorial_done .factorial_loop: mul bx ; AX BX dec bx ; BX-- jnz .factorial_loop .factorial_done: ret factorial endp main endp end main
Explanation of the Program
The program comprises several main components:
Data Segment: Declares strings for messages and a buffer to store the input number. Input Handling: Prompts the user for a number and reads it, converting it from a string to an integer. Factorial Calculation: Calculates the factorial of each digit using a separate factorial procedure. Sum Calculation: Sums the factorials of the digits and compares the sum with the original number. Output: Depending on the comparison, it prints whether the number is a strong number or not.Running the Program
To run this program, you will need an 8086 emulator or assembler like MASM or TASM. Assemble the code, link it, and run the resulting binary. The program will prompt you to enter a number and then determine if it is a strong number.
About the Keywords
The keywords for this article include 8086 assembly, which refers to the assembly language used for programming the Intel 8086 microprocessor, and strong numbers, which are numbers where the sum of the factorials of its digits equals the number itself. The third keyword is factorial calculation, which plays a crucial role in determining if a number is a strong number.
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